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2y^2+6y-108=0
a = 2; b = 6; c = -108;
Δ = b2-4ac
Δ = 62-4·2·(-108)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-30}{2*2}=\frac{-36}{4} =-9 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+30}{2*2}=\frac{24}{4} =6 $
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